GATE AE 2025 • Q33 MCQ • 1 Mark

Aerospace Structures

Thin-Walled Structures

Subtopic: Shear Flow in Open and Closed Thin-Walled Beams

Question Statement:

A gaseous fuel mixture comprising 3 moles of methane and 2 moles of ammonia is combusted in X moles of pure oxygen in stoichiometric amount. Assuming complete combustion, with only CO2, H2O and N2 in the product gases, the value of X is ___. 3 CH4 + 2 NH3 + X O2 → Products (CO2, H2O, N2)

Options:

  • (A) 7.5
  • (B) 5.5
  • (C) 8.5
  • (D) 9.5

Official Answer Key:

A

Step-by-Step Solution & Explanation

### **Detailed Step-by-Step Solution (GATE AE 2025 Q.33)** **1. Intuitive Physical Setup & Given Parameters**: Combustion of a gaseous fuel mixture in pure oxygen: - 3 moles of methane ($\text{CH}_4$) - 2 moles of ammonia ($\text{NH}_3$) - $X$ moles of oxygen ($\text{O}_2$) - Complete stoichiometric combustion producing only $\text{CO}_2$, $\text{H}_2\text{O}$, and $\text{N}_2$: $3\,\text{CH}_4 + 2\,\text{NH}_3 + X\,\text{O}_2 \to a\,\text{CO}_2 + b\,\text{H}_2\text{O} + c\,\text{N}_2$ We need to determine the stoichiometric moles of oxygen $X$. **2. Step-by-Step Chemical Stoichiometry Derivation**: 1. **Carbon (C) Balance**: - Reactants: $3 \times 1 = 3$ moles of C. - Products: $a$ moles of $\text{CO}_2$. $a = 3$ 2. **Nitrogen (N) Balance**: - Reactants: $2 \times 1 = 2$ moles of N. - Products: $2c$ moles of N in $c\,\text{N}_2$. $2c = 2 \implies c = 1$ 3. **Hydrogen (H) Balance**: - Reactants: - From $3\,\text{CH}_4$: $3 \times 4 = 12$ atoms of H. - From $2\,\text{NH}_3$: $2 \times 3 = 6$ atoms of H. - Total H atoms $= 12 + 6 = 18$ atoms. - Products: $2b$ atoms of H in $b\,\text{H}_2\text{O}$. $2b = 18 \implies b = 9$ 4. **Oxygen (O) Balance**: - Reactants: $2X$ atoms of O in $X\,\text{O}_2$. - Products: - In $3\,\text{CO}_2$: $3 \times 2 = 6$ atoms of O. - In $9\,\text{H}_2\text{O}$: $9 \times 1 = 9$ atoms of O. - Total O atoms in products $= 6 + 9 = 15$ atoms. - Equating Oxygen atoms: $2X = 15 \implies X = \frac{15}{2} = 7.5\text{ moles}$ **3. Comprehensive Options & Distractor Analysis**: - **(A) 7.5**: ✅ **CORRECT**. $X = 3(2) + 2(0.75) = 6 + 1.5 = 7.5\text{ moles}$. - **(B) 5.5**: ❌ **INCORRECT**. Misses water from ammonia. - **(C) 8.5**: ❌ **INCORRECT**. Overcounts oxygen atoms. - **(D) 9.5**: ❌ **INCORRECT**. Arithmetic error in hydrogen summation. **4. Official Master Key & Exam Takeaway**: - **Official Answer Key**: **A** - **Exam Takeaway**: Independent mole balance: $\text{CH}_4 + 2\text{O}_2 \to \text{CO}_2 + 2\text{H}_2\text{O}$ (needs 2 $\text{O}_2$/mol), $\text{NH}_3 + 0.75\text{O}_2 \to 0.5\text{N}_2 + 1.5\text{H}_2\text{O}$ (needs 0.75 $\text{O}_2$/mol). Total $\text{O}_2 = 3(2) + 2(0.75) = 7.5$.

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